The equation x2 + y2 − 2x + 2y − 1 = 0 is the general form of the equation of a circle. What is the standard form of the equation? (x − 1)2 − (y − 1)2 = 1
the standard form of a circle would not have the minus sign between the two squares
(x − 1)2 − (y − 1)2 = 1 (x − 1)2 + (y + 1)2 = 3 (x + 1)2 + (y − 1)2 = 1 (x − 1)2 + (y + 1)2 = 1
those are the answer choices
did you intend that (x − 1)2 − (y − 1)2 = 1 would represent one of the four answer possibilities?
no, that was one of the answer choices
You are likely to convey your math to others (and perhaps to yourself as well) if you'd please type the square of (x-1) as (x-1)^2 OR \[(x-1)^2\]OR|dw:1400119244802:dw|
OK: now, using Satellite73's obstervation, eliminate the answers that could not be correct. Then think about how to narrow down further to obtain the correct answer. strong hint: use "completing the square" to help y ourself identify the center (h,k) of this circle.
it's either C or D
As always I'm going to ask you to justify (give reasons for) your answer(s).
may i please just have the answer
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