They want me to write the problem in SIMPLEST RADICAL FORM. Am I doing it right?
\[\sqrt{n}\sqrt[3]{n}\sqrt[6]{n}\] is this \[n ^{1/2}\]
they are being multiplied
no since \(\sqrt{n}=n^{\frac{1}{2}}\)
Would the answer just be \[\sqrt{n}\sqrt[3]{n}\sqrt[6]{n}\] as the simplest it could go
Hint: It may help you to see what needs to be done if you'd please re-write this expression as \[n ^{1/2}*n ^{1/3}*n ^{1/6}\]
Hint: referring to "rules of exponents," what is\[x^a*x^b, ~when~ simplified?\]
would it be \[n^{a+b}\] so 3/6 + 2/6 + 1/6 = 6/6, which is 1. So just n would be the answer?
Yes, and that's very nice work on your part!
Thanks, I appreciate the help! Could I ask you one more like this
Sure, but would you please post it as a separate question.
Ok! I'm about to, no problem
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