a ball is thrown upward from the top of a building, the function below shows the height of the ball above the ground f(t)in feet at different times (t) in seconds: f(t)=-16t^2+32t+90 the average rate of change of f(x) from x=4 to x=6 is?
@ranga
@sourwing
Isn't it just (f(6) - f(4))/2?
im not sure @IAmSinged
@iambatman
yeah it's just the change in f(x) divided by the change in x. http://tutorial.math.lamar.edu/Classes/CalcI/Tangents_Rates.aspx
wait so you just dived 4 by 6?
@jim_thompson5910
You're finding the slope between the 2 pts. I know the change in y (f(6) - f(4)), and I know the change of x (6 - 4 = 2). Then I just divide the change in y by the change in x, because that's the definition of the slope.
im confused :/
You want to find the slope between the points at t = 4 and t = 6 (definition of average rate of change). You get the y values of the points by plugging it into the equation. At t = 4, we get -38. At t =6, we get -294. So we have the points (4, -38) and (6, -294) and we want to find the slope. So we do: (-294 + 38)/(6 - 4) = -128.
The average rate of change of a function, f(x), between x = a and x = b is defined as: \[\frac{f(b) - f(a)}{b-a}\]
You can prove that the slope between the two points is the average rate of change by finding the derivative divided by the change in x, and then integrating it.
@ranga so I would plug In 4 and 6? f(4)-f(6) /4-6
Yes, but I would do it the other way (you will get the same answer): { f(6) - f(4) } / { 6 - 4}
is the answer 1?
@ranga ?
No, that is not the answer. f(6) = ? f(4) = ?
6 and 4 right?
f(t)=-16t^2+32t+90 f(6) = -16(6)^2 + 32(6) + 90 = ? f(4) = -16(4)^2 + 32(4) + 90 = ?
f(6)=-294 f(4)=-38
Yes. Plug it into \[\frac{f(6) - f(4)}{6-4}\]
-294 - (-38) /-294 -(-38) =-256/-256?
\[ \frac{f(6) - f(4)}{6-4} = \frac{-294+38}{2} = \frac{-256}{2} = -128 ~ft./sec \]
ohhhhh
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