Question

For the given statement Pn, write the statements P1, Pk, and Pk+1.

2 + 4 + 6 + . . . + 2n = n(n+1)

Answer 1

@Chad123

Answer 2

2 = 1*(1 + 1) = 2

Answer 3

\(P_1\) is what you get when you replace \(n\) by \(1\) namely
\[2=1(1+1)\]

Answer 4

2 + 4 + ... + 2n + 2(n+1) = (n + 1)(n + 2)

Answer 5

okay so i got that right
for Pk I replaced the Ns with Ks. Is that right?

Answer 6

\(P_k\) is what you get when you replace \(n\) by \(k\)

Answer 7

\[2 + 4 + 6 + . . . + 2n = n(n+1) \]replace \(n\) by \(k\) get
\[2 + 4 + 6 + . . . + 2k = k(k+1) \]

Answer 8

Is that all i have to do to get Pk?

Answer 9

yes believe it or not, that is all

Answer 10

how do I do the end?

Answer 11

replace \(n\) by \(k+1\)
use parentheses

Answer 12

so it would be
k+1*(k+1)+1)?