Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

Write in simplest radical form

OpenStudy (anonymous):

\[\sqrt[4]{27}\times \sqrt[8]{9}\]

OpenStudy (anonymous):

@mathmale so does the 4 become (to the 1/4 power) and the 8 (to the 1/8) power?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

When I did this on Mathway, I got \[27^{0/4}\]

OpenStudy (anonymous):

\[27^{1/4}*9^{1/8}\]

OpenStudy (anonymous):

So that's as far as you can possibly go? They didn't say to solve, just write in simplest radical form

OpenStudy (anonymous):

just keep going

OpenStudy (anonymous):

\[(27*9)^{1/4+1/8}\]

OpenStudy (anonymous):

\[243^{3/8}\]

OpenStudy (anonymous):

The answer is 3!

OpenStudy (anonymous):

\[\sqrt[8]{243^{3}}\]

OpenStudy (mathmale):

Strong suggestion: Rewrite your\[\sqrt[4]{27}\times \sqrt[8]{9}\]as\[27^\frac{ 1 }{ 4 }*9^{\frac{ 1 }{ 8 }}\]

OpenStudy (mathmale):

Recognize that this result is the same as \[(3^3)\ ^{ \frac{ 1 }{ 4 }}*(3^2)^{\frac{ 1 }{ 8} }\]

OpenStudy (mathmale):

See if you can simplify this.

OpenStudy (mathmale):

Hints:\[(a^x)^y=a ^{xy}\]and\[a^x*a^y=a ^{x+y}\]

OpenStudy (anonymous):

So it would be \[(3^{5})^{3/8}\]

OpenStudy (anonymous):

\[243^{3/8}\]

OpenStudy (mathmale):

\[(3^3)\ ^{ \frac{ 1 }{ 4 }}*(3^2)^{\frac{ 1 }{ 8} }\] simplifies to \[3^{3/4 }*3^{1/4}\] Please check that out and then simplify this last expression. Compare your result to 243^(3/8).

OpenStudy (anonymous):

\[3^{4/4}\] which equals 3

OpenStudy (mathmale):

does that agree with any of your answer choices?

OpenStudy (anonymous):

This one wasn't multiple choice, they just wanted me to write the problem in simplest radical form in the blank! But I've never done one like this before, so seeing the steps to solve it really helps a lot. Thank you so much

OpenStudy (mathmale):

You're very welcome, and I hope to have the pleasure of working with y ou again!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!