Write in simplest radical form
\[\sqrt[4]{27}\times \sqrt[8]{9}\]
@mathmale so does the 4 become (to the 1/4 power) and the 8 (to the 1/8) power?
yes
When I did this on Mathway, I got \[27^{0/4}\]
\[27^{1/4}*9^{1/8}\]
So that's as far as you can possibly go? They didn't say to solve, just write in simplest radical form
just keep going
\[(27*9)^{1/4+1/8}\]
\[243^{3/8}\]
The answer is 3!
\[\sqrt[8]{243^{3}}\]
Strong suggestion: Rewrite your\[\sqrt[4]{27}\times \sqrt[8]{9}\]as\[27^\frac{ 1 }{ 4 }*9^{\frac{ 1 }{ 8 }}\]
Recognize that this result is the same as \[(3^3)\ ^{ \frac{ 1 }{ 4 }}*(3^2)^{\frac{ 1 }{ 8} }\]
See if you can simplify this.
Hints:\[(a^x)^y=a ^{xy}\]and\[a^x*a^y=a ^{x+y}\]
So it would be \[(3^{5})^{3/8}\]
\[243^{3/8}\]
\[(3^3)\ ^{ \frac{ 1 }{ 4 }}*(3^2)^{\frac{ 1 }{ 8} }\] simplifies to \[3^{3/4 }*3^{1/4}\] Please check that out and then simplify this last expression. Compare your result to 243^(3/8).
\[3^{4/4}\] which equals 3
does that agree with any of your answer choices?
This one wasn't multiple choice, they just wanted me to write the problem in simplest radical form in the blank! But I've never done one like this before, so seeing the steps to solve it really helps a lot. Thank you so much
You're very welcome, and I hope to have the pleasure of working with y ou again!
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