Help please... Let f(x)=-2x+4 and g(x)=-6x-7. find f(x)-g(x)
put them in parentheses, then put a minus sign between them
(-2x+4)-(-6x-7) like this? @satellite73
yes then distribute the minus sign for the second parentheses, and combine like terms
4x-3
close but you did not distribute completely
\[(-2x+4)-(-6x-7) =-2x+4+6x+7\]
4x+11 I am confused
your second answer is correct
when you distribute the minus sign, you have to change the sign if each term you see
Oh okay thank you! can you help me with 2 more questions?
sure
heres one what is the inverse of the given relation? y=3x+12
wow we really stepped it up from the last one!
can you solve \[y=3x+12\] for \(x\)?
Yeah. 12+y=3x 4y=x how would i get y alone now.
hmm lets start at the beginning
I know i have to get x alone
\[y=3x+12\] and we want to solve for \(x\) before i do it, let me ask you a question do you have answer choices? or do you have to come up with it on your own i just want to know what the choices look like before we start
i have to type it all out i dont have answer choices.
ok i was asking because i don't know if your answer is suppose to look like \(y=something\) or \(x=something\) but not matter lets solve for \(x\)
\[y=3x+12\] solve for \(x\) in two steps 1) subtract \(12\) from both sides 2) divide both sides by \(3\)
\[y=3x+12\\ y-12=3x\\ \frac{y-12}{3}=x\]
i know you get 4
i dont know where to put it lol
the reason i was asking the previous question is because i dont know if your answer is supposed bo be \[y=\frac{x-12}{3}\] or \[x=\frac{y-12}{3}\]
i am not sure what you mean
i was dividing but now i get it.
yeah when i say "divide' i don't really mean do a division, i just mean write it
Oh okay. I have one more i need help on. rewrite 3^sqrt(27x-81-5) to make it easy to graph using a translation.
is this really \[\sqrt[3]{27x^2-81-5}\]? seen unlikely
yes.
i have no idea repost this as a new question and maybe you will get a good answer
I figured it out thank you though!
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