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Mathematics 14 Online
OpenStudy (anonymous):

Trevor is tiling his bathroom floor, which has an area that is represented as 117r4 square inches. Each tile has an area of square root of the quantity 9 r to the thirteenth power . The total number of tiles used can be represented by the expression below. one hundred seventeen r to the fourth power, all over the square root of the quantity nine r to the thirteenth power Simplify the expression for the total number of tiles used. Show your work

OpenStudy (anonymous):

OpenStudy (johnweldon1993):

Alright...so firstly....what is the square root of 9?

OpenStudy (anonymous):

3

OpenStudy (johnweldon1993):

Right...so we can bring that 3 out of the radical \[\large \frac{117r^4}{3\sqrt{r^{13}}}\] like that...okay?

OpenStudy (johnweldon1993):

Now, we also know that r^13 can be broken up like: \[\large r^{13} = r^9 \times r^4\] right?

OpenStudy (anonymous):

well it would be 3r^6 sqrt r

OpenStudy (johnweldon1993):

I'm not sure what you mean...explain please :)

OpenStudy (anonymous):

in the denominator, there is an exponent of 13, you could take one out which would leave r*r^12. The r^12 could be simplified to r^6 outside of the sqrt, leaving it 3r^6sqrt(r)

OpenStudy (johnweldon1993):

Great job! I was going to do it another way...which would have taken 1 more step...but yes good workaround :) so now we just have \[\large \frac{117r^4}{3r^6\sqrt{r}}\] Now we can simplify by doing...117/3 = 39 ad r^4/r^6 = r^{4 - 6} = r^-2 so pretty much at the very end we can have \[\large \frac{39r^{-2}}{\sqrt{r}}\] or\[\large \frac{39}{r^2\sqrt{r}}\] if you still wanted to simplify the denominator you definitely can :)

OpenStudy (anonymous):

ok thank you!

OpenStudy (johnweldon1993):

Anytime :)

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