Question

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1. Draw a 30-60-90 triangle. Label all angle measures and side relationships. Using the side relationships from the figure, show that the following trigonometric identities hold true for the given angles:

Answer 1

\[A) \tan 60 degrees \frac{ \sin 60 degrees }{ \cos 60 degrees }\]
\[B) Sin ^{2} (30 degrees) + \cos ^{2} (30 degrees) = 1\]

Answer 2

@Kamizamurai

Answer 3

@tester97

Answer 4

sorry im not good with trig

Answer 5

Do you know anyone who is? This is my geometry study guide and I dont remember learning this.

Answer 6

No i dont but if you are in connections academy im sure you can go and watch the live lesson recordings

Answer 7

I am not in connections actually. But thanks @tester97

Answer 8

@linda3

Answer 9

i can prove both......
see........\[\sin x=\frac{ ooposite side of x }{ hypotenuse}\]

\[\cos x \frac{ adjacent side of x }{ hypotenuse }\]

\[\tan x =\frac{ opposite side of x }{ adjacent side of x }\]
multiply by hypotense and divide by hypotenuse,we get,
\[\tan x=\frac{ opposite side of x }{ adjacent side of x }\times \frac{ hypotenuse }{ hypotenuse } = \frac{ \frac{ opposite side of x }{ hypotenuse } }{ \frac{ adjacent side of x }{ hypotenuse } } =\frac{ \sin x }{ \cos x }\]
hence proved

Answer 10

@aaryaancoool is that the answer oooor?

Answer 11

yupp

Answer 12

2nd proof
\[k ^{^{2}} + n ^{2}=b ^{^{2}}\
this is the pyth. theorem......
k=opposite side to x,n=djecent side of x
b=hypotenuse
divide the eqn by b\[\sin x ^{2}+ \cos x ^{^{2}}=1\]
proved

Answer 13

Wait but what does that have to do with the 30-60-90 triangle? @aaryaancoool

Answer 14

pythagoras theorem is applied for a right angled triaangle,my friend,& i believe 30-60-90 triangle is a right angle tiangle....

Answer 15

you can consider as any angle you have to work out....