Complete and balance the following equation. Then write it as a net ionic equation. K3PO4(aq) + MgCl2(aq)

Question

anonymous · Answer

2 K3PO4(aq) + 3 MgCl2(aq) -----> Mg3(PO4)2 + 6 KCl
maybe?

highschoolmom2010 · Answer

how did you do it ? i dont understand this

anonymous · Answer

Assuming the product were an association of the anions and cations of the reagent I knew Mg was to combine with PO4 and K with Cl, knowing the charges such as Mg2+, K+, Cl- and PO4^3- I equilibrated the charges so that the compound would be neutral, to do that I had to change the stoechiometric factor of the reagent

highschoolmom2010 · Answer

ok what is a stoechiometric factor?

anonymous · Answer

That's the number of atoms, as an example:
3 Mg+ , 3 is the stoechiometric factor

highschoolmom2010 · Answer

ok so how how do i do the net ionic equation?

anonymous · Answer

If you write the net ionic, you have to exclude the ionic spectator, Mg3(PO4)2 is insoluble so it will precipitate , K+ and Cl- are the spectator, so if you exclude them from the reaction you get :
3 Mg^2+(aq) + 2PO4^3-(aq) ---> Mg3(PO4)2(s)