Question

Identify the 16th term of a geometric sequence where a1 = 4 and a8 = -8,748

Answer 1

first term a1=4
and a8=-8748
if r=common ratio then \[a1*(r ^{7})=-8748\]
\[r ^{7}=\frac{ -8748 }{ 4 }=-2187\]
r=3 now
16th term
\[a1*(r ^{15})=4*(3^{15})\]

Answer 2

so then I multiply and simplify. giving me the answer? or is there more to simplify?

Answer 3

yes multiply and simplify

Answer 4

so would it be -57,395,628? or is my math off?

Answer 5

yup

Answer 6

thanks!