Question

Use the discriminant to determine the number and type of solutions the equation has.

x^2 + 6x + 12 = 0

A. one real solution
B. two rational solutions
C. no real solution
D. two irrational solutions

Answer 1

@jigglypuff314

Answer 2

I don't think it's A or B

Answer 3

x2 + 2x – 2 = 0

Discriminant = b^2 - 4ac, a = 1, b = 2, c = - 2


= (2)^2 - 4(1)(- 2)

= 4 + 8

= 12 D)

Answer 4

So it's D?
Thought so! Thanks :)

Answer 5

I thought it was C...
http://www.wolframalpha.com/input/?i=x%5E2+%2B+6x+%2B+12+%3D+0+

Answer 6

I can't read that o.O
Can you explain in your own words, Emily? XP

Answer 7

it does not touch the x axis so there are no real solutions
because solutions come from when the graph touches the x axis

Answer 8

Mmm, confusing... o.O

Answer 9

oh, jordanloveangle wrote a -2 instead of a 12

Answer 10

Sooooo...?

Answer 11

x2 + 2x + 12 = 0

Discriminant = b^2 - 4ac, a = 1, b = 2, c = 12
= (2)^2 - 4(1)(12)
= 4 - 48
= negative -> means no real solutions
http://www.mathwarehouse.com/quadratic/discriminant-in-quadratic-equation.php

Answer 12

Mmm, makes sense :)
I agree with you

Answer 13

Emily, how about this one?

What number would you have to add to both sides to complete the square?

x^2 – 14x = 7

A. –49
B. 196
C. –196
D. 49

I think D.

Answer 14

correct :)

Answer 15

Yesh :D
Thanks :)