Question

I need help figuring this one out..

Answer 1

@Marv93w

Answer 2

so we need to get x by itself what is the first thing step we can do in making x a loner?

Answer 3

subtract 4 from each side..

Answer 4

Well both 4s so... subtract 8 from each side.

Answer 5

but that second 4 is under the sqrt sign so we can't yet just move that first 4. the next step is to get the sqrt sign the fsk out of there

Answer 6

Yes. So it looks like:
\[\sqrt{6x+4} =12\]

Answer 7

Correct?

Answer 8

well you added 4 on the right side and took away 4 on the left. remember an equation means that pellet here = pellet here. So what you do to one side you do to the other. so nope not correct. But close

Answer 9

Sorry that was me being a dork xD let me redo that:
\[\sqrt{6x+4} =4\]

Answer 10

yeeee! ok so now i want to get rid of the sqrt sign... how do i do that?

Answer 11

Square it?

Answer 12

@Marv93w What do I do from here?

Answer 13

I'm at,
\[\sqrt{6x+4} =4\]

Answer 14

you square both side so you can take out the radical sign

Answer 15

sooo.... 6x^2+16=16?