Question

Write an equation in standard form parallel to y=3x-2 through the point (5,6)

Answer 1

do you know what the slope of \[y=3x-2\] is?

Answer 2

I have no idea.. I'm really bad at this :/

Answer 3

-2?

Answer 4

\[\large y = \color{red}mx+\color{blue}b\] has slope \(\color{red}m\) and \(y\) intercept \(\color{blue}b\)

Answer 5

So it would be y=-2x+3?

Answer 6

@Reaper534 ??

Answer 7

?
we are still working on finding the slope of
\[\large y=\color{red}3x-2\]

Answer 8

is it 3?

Answer 9

yes it is !

Answer 10

Yay! ok so i have to make an equattion with the points 5,6 in it

Answer 11

Write an equation in standard form PARALLEL to y=3x-2
now means find the equation of the line with slope \(\color{red}3\) through \((5,6)\)
right, exactly

Answer 12

Can you tell me how to do that?

Answer 13

yes

Answer 14

Ok so what do I do first

Answer 15

write
\[\large y-\color{green}{y_1}=\color{red}m(x-\color{blue}{x_1})\] with
\[\large \color{red}m=\color{red}3,\color{blue}{x_1}=\color{blue}5,\color{green}{y_1}=\color{green}6\]

Answer 16

let me know what you get

Answer 17

is that the answer?

Answer 18

type it in and i will tell you
there is another step after that

Answer 19

Well thats all i really needed.. all i need is to write the equation and thats all

Answer 20

y−y1=m(x−x1)
with
m=3,x1=5,y1=6

Answer 21

no actually you need to write it in standard form
that is not standard form

Answer 22

ok can you help me put it in stardard form?

Answer 23

i will after you make the replacements and tell me what you get

Answer 24

you wrote

y−y1=m(x−x1)
with m=3,x1=5,y1=6

which is what i wrote, explaining how to do it
you need to make those replacements

Answer 25

y-6=3(x-5)

Answer 26

got it

Answer 27

ok

Answer 28

I have an other question

Answer 29

that is "point slope" form
you need "standard " form
the next step is to multiply out on the right

Answer 30

you may have other questions, and i will help if i can, but this one is not done yet

Answer 31

y-6=3x-15?

Answer 32

is that it??

Answer 33

that is the next step, yes

Answer 34

ok

Answer 35

now add \(6\) to both sides to get \(y\) by itself

Answer 36

y=3x-9

Answer 37

ok good
now it is in "slope intercept" form

Answer 38

ok

Answer 39

do i divide?

Answer 40

to put it in "standard form" put the \(x\)'s and \(y\)'x on one side of the equal sign, the number on the other

Answer 41

no no division

Answer 42

-3x+y=-9?

Answer 43

\[y=3x-9
\] is "slope intercept" form
\[3x-y=9\] is "standard" form

Answer 44

ohhhh ok

Answer 45

yours is good too, but mostly the \(x\) term comes first with a positive coefficient
so while
\[-3x+y=-9\] is one answer, most people write
\[3x-y=9\]

Answer 46

Ohhhh ok :) thanks! I have an other question

Answer 47

k go ahead and ask
what class is this for?

Answer 48

solve for f(x)=x^2-4x+3
f=-2

Answer 49

Algebra ll D:

Answer 50

Im just practicing with some questions in the book

Answer 51

is it "find \(f(-2)\)" or is it
solve \(f(x)=-2\) ?

Answer 52

first one

Answer 53

\[\large f(\diamondsuit)=\diamondsuit^2-4\diamondsuit+3\]

Answer 54

replace \(\diamondsuit\) by \(-2\)
use parentheses

Answer 55

There are diamonds in the way

Answer 56

OHHHH

Answer 57

then sell them

Answer 58

Ok i did that. Do i multiply

Answer 59

you compute
\[(-2)^2-4\times (-2)+3\]

Answer 60

WHat?

Answer 61

\[f(x)=x^2-4x+3 \]
\[f(-2)=(-2)^2-4\times (-2)+3 \]

Answer 62

let me know when you get \(15\)