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Verify the identity. 1-sinx/cosx=cosx/1+sinx
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@mathslover any idea?
I cant do trig >.< i terrible at it ~ sorry wish i cud help :/
@arabpride know anyone that could?
@*Insert Name Here*
Multiply by the conjugate
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sorry but what part is the conjugate, (I'm really bad at pre calc)
You have \(\Large \frac{1-sinx}{cosx}=\frac{cos}{1+sinx}\) Correct? Multiply by \(1+sinx\) \(\Large \frac{1-sin^2 x}{(cosx)(1+sinx)}\) Use the identity \(sin^2x+cos^2=1\) here So you end up with \(\Large \frac{cos^2x}{cosx(1+sinx)}\) Cancel a cos from the top and bottom leaving you with \(\Large \frac{cosx}{1+sinx}=\frac{cosx}{1+sinx}\)
Make sense?
yes perfect sense, THANK YOU!!
You're welcome~
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