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Use the substitution method to solve the following system of linear equations: 2x + 2y = 10 x = –y + 5
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A. The solution is (4, –1). B. There are an infinite number of solutions. C. There is no solution. D. The solution is (2, –3).
x = -y + 5 now sub -y + 5 in for x in the other equation 2x + 2y = 10 2(-y + 5) + 2y = 10 -2y + 10 + 2y = 10 -2y + 2y = 10 - 10 0 = 0 INFINITE SOLUTIONS That is using the substitution method, but if you look at the equations.. x = -y + 5 x + y = 5 2x + 2y = 10 -- divide by 2 x + y = 5 you will see that they are the same line and therefore have infinite solutions.
thanks
sure thing :)
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