a right triangle has base(x-6)units and a hight (6x-12) units
what is the square of the hypotenuse of the triangle
what is the area of the triangle
using the area explain the clouser property of multiplication of polynomials
can you fill in what we know on the triangle? |dw:1400268546425:dw|
|dw:1400269724786:dw|
great, now the pythagorean theorem says sides a and b, when squared equals the hypotenuse, c. a^2 + b^2 = c^2 |dw:1400269953970:dw| can you do a^2 + b^2?
I don't get how to do that
?
if a is (x-6) and b is (6x-12) and i subtute them into a^2 + b^2 it becomes (x-6)^2 + (6x-12)^2
(x^2-36)+(6x^2-144) ?
mmm... not quite (x-6)^2 is the same as (x-6)(x-6), now FOIL
x^2-6x-6x-36
great, just combine like terms so you get -12x now FOIL the other one too, (6x-12)^2
so foil (6x-12)and (6x-12)
yep ^_^
36x^2-72-72+144?
yep, just rmember its 72x, not just 72 36x^2-144x + 144
a^2 + b^2 becomes (x^2-12x-36) + (36x^2-144x + 144) now simpify
do I foil?
nope, its like this: (x^2-12x-36) + (36x^2-144x + 144) x^2-12x-36 + 36x^2-144x + 144
just simplify
36x^4-156x^2+108?
close! 37x^2 -156x +108 36x^2 + x^2 = 37x^2
don't u add the exponets tho?
"what is the square of the hypotenuse of the triangle" its this 37x^2 -156x +108 becuase if the hypotenuse is 'c' and we did a^2 + b^2= c^2
and y 37?
here are the rules: when adding terms that have the same power on the x's, we just sum the coefficeints when multipying terms we add the exponents and times the coefficients
ooo ok thanks
do I just add to get c now
if this is c, "using the area explain the clouser property of multiplication of polynomials" I haven't the slightest idea what it means :(
no the hyp "c"
or is it done
ok sorry the question says"what is the square of the hypotenuse of the triangle" we named the hypotenuse 'c' and it is asking for the squre of the hypotenuse, so that would be "c^2" and we did a^2 + b^2 = c^2 37x^2 -156x +108 = c^2
ya, we got it hey, i gotta log off now. good job today ^_^
thanks again
^_^
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