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Mathematics 11 Online
OpenStudy (anonymous):

You roll a standard number cube once. Find P(0).

OpenStudy (anonymous):

@Hero please help me

OpenStudy (accessdenied):

I assume P(0) is probability of rolling a 0. That said, how are the numbers on a standard number cube labelled? Do we have a face with value 0?

OpenStudy (anonymous):

let me show you the answers

OpenStudy (anonymous):

7/6 1 1/2 0

OpenStudy (accessdenied):

Right. In a standard number cube, the numbers are labelled 1 through 6, right? We don't have a value for 0. So there is no way we can roll a 0. Or setting it up like this: Probability = # favored outcomes / # total outcomes # favored (rolling a 0) = 0 ways. (there is no 0 face) # total = 6 ways Probability = 0 / 6, which is just 0.

OpenStudy (anonymous):

thanks

OpenStudy (accessdenied):

you're welcome! :)

OpenStudy (anonymous):

wait can you help me on more

OpenStudy (accessdenied):

How many more?

OpenStudy (anonymous):

3

OpenStudy (anonymous):

please

OpenStudy (accessdenied):

Sure, I will try. :)

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

Clarissa is having lunch at a sandwich shop. She can choose white bread or pumpernickel bread. Her options for fillings are turkey, tuna, ham, or egg salad. Her choices for condiments are mayonnaise, salad dressing, or mustard. How many different sandwich choices does Clarissa have?

OpenStudy (accessdenied):

When counting these combinations, we can multiply the quantity of each choice together to get the total number of choices. (2 breads) * (4 fillings) * (3 condiments) So just simplify 2*4*3 and that will be the answer!

OpenStudy (anonymous):

24?

OpenStudy (accessdenied):

Yes, looks good!

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Janelle wants to buy a shirt for a friend. Her choices of material are polyester and cotton. Shirts are available in yellow, orange, and blue. Make an organized list showing the different choices Janelle has

OpenStudy (accessdenied):

Well, each choice will be out of the two sets. {polyester, cotton}. {yellow, orange, blue}. So a systematic way to list these is just write down the first choice paired with each in the second group, then the second choice with each in the second group. Example: Polyester - Yellow Polyester - Orange and so on. Does that seem clear?

OpenStudy (anonymous):

no

OpenStudy (accessdenied):

There are two types of material, and for each material there are three colors. So we could find the first material with any color, then the second material with any color. We're just listing all the possible options here, Polyester with Yellow, Orange, and Blue; Cotton with Yellow, Orange, and Blue. If I could explain something in particular to clear up any doubts that would be best. :)

OpenStudy (anonymous):

oh got it

OpenStudy (anonymous):

A party store offers small balloons and large balloons. You can choose from pink, blue, green, and yellow balloons. You can choose from silver, gold, and white ribbons. Use the counting principle to find the number of different ways you can choose a balloon with a ribbon.

OpenStudy (accessdenied):

Counting principle is just like the sandwich shop problem. If there are some number of ways to do one thing, then some number to do another; we just multiply the number of ways of each for the total number of ways doing both. (a) We can choose from pink, blue, green, and yellow balloons. How many options? (b) We can choose from silver, gold, and white ribbons. How many options? The total number of different choices is then just the product of the numbers from (a) and (b).

OpenStudy (anonymous):

thanks

OpenStudy (accessdenied):

Glad to help!

OpenStudy (anonymous):

sorry I wasn't here to hlp

OpenStudy (anonymous):

no problem

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