If you charge a comb by rubbing it against fur and place it near scrap bits of paper, what will happen? (Points : 1) The comb will repel the bits of paper by induction. The comb will attract the bits of paper by charge polarization. The comb will repel the bits of paper by charge polarization. The comb will attract the bits of paper by conduction.
That is first one....... the comb will attract the bits of paper by charge polarizaton
Induction only occurs with conductors, and paper isn't a conductor. Conduction only happens with, uhm, conductors. So that leaves two options for the answer: B or C. The electric static charge accumulated on the comb will force the electrons to redistribute so that a charge opposite that of the comb is on the paper facing the comb. That means the answer is the second one, B: "The comb will attract bits of paper by charge polarization."
Oh, That makes sense! Thank you so much. I understand it now. :)
I have a few more questions on this study guide that I don't understand and would appreciate the help on!
Object A experiences an attractive force of 50 N when it comes close to Object B. If Object A is positively charged, what can you say about Object B? (Points : 1) Object B is neutral. Object B is positively charged. Object B is negatively charged. You cannot tell from the information given.
@IhteshamMalik
@PsiSquared
A is positively charge then B will be Negatively charged because opposite charges attract each other
" Two oppositely charged objects will attract each other".... while " two objects have similar charge will repel each other"... if force is attractive between objects it means one object is +ve and 2nd is surely negative charged....
do you got it @Imckenzie3
Yup, an attractive electric force is only manifested between opposite charges. Like charges repel each other.
Oh okay! I got it. Thanks you guys.
No mention brother.... Gain knowledge and spread it.... THats our duty.... because we are not The Owner of knowledge.... we are just selected to convey knowledge .....
How many coulombs could be in a lightening bolt? 1. 6 × 1019 C 5.0 × 106 C 5.0 × 100 C 6.24 × 1018 C
Can you help me with this question please? @IhteshamMalik
Thats the 4th answer... 6.24 ..........
Okay, what about this question? An object with a charge of +6.0 µC is 0.30 m from a second object and experiences an attractive force of 1.80 N. What is the magnitude of the charge on the second object? (Points : 1) -6.0 μC -3.0 μC +3.0 μC +6.0 μC
Coulomb's law is applied for its solution
that is \[F = k \frac{ pq }{ ^{r2} }\]
where p is first charge and q is 2nd we also write them q1 and q2
In the question we know " r= distance between them" F = force between them and k is a constant and charge of "p" is known but of "q" is to find
q = Fr^2 / kp
So would it be -3.0?
YEs
is it clear to you now?
I'm still slightly confused. Can we try this question? Two identical objects each with a charge of +3.0 µC experience a repulsive force of +0.90 N between them. How far apart are the objects? (Points : 1) 0.10 m 0.20 m 0.30 m 0.90 m
in the above given formula... r is the distance between the charged objects... okay??? and Force between them denoted by "F" charges are denoted by p and q
Now the charged objects are identical it means the both have same charge and same magnitude of charge.... p = q = + 3 \[ \mu\]
Now force is repulsive.... we just have to find the distance between them..... okay now from that formula we have r = \[\sqrt{\frac{ kpq }{ F }}\]
the answer is 0.3 m
Great, thanks!
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