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Mathematics 8 Online
OpenStudy (anonymous):

The sum of the reciprocals of two consecutive even integers is 7/24. Write an equation that can be used to find the two integers. Find the two integers.

OpenStudy (anonymous):

OpenStudy (anonymous):

@DemolisionWolf

OpenStudy (campbell_st):

start with the basics the consecutive even integers are x and x + 2 their reciprocals are \[\frac{1}{x} ...and.... \frac{1}{x + 2}\] then using the sum you have \[\frac{1}{x} + \frac{1}{x + 2} = \frac{7}{24}\] so this requires a common denominator on the left \[\frac{(x +2) + x}{x(x+2)} = \frac{7}{24}\] simplify and cross multiply and you get \[24(2x + 2) = 7(x^2 + 2)\] which becomes \[7x^2 - 34x -48 = 0\] so the quadratic... for x.... and you'll have the value for x.... I'd recommend the general quadratic formula... only use the answer for the positive even integer... hope it helps

OpenStudy (anonymous):

i put the wrong attachment :O @campbell_st its this one

OpenStudy (campbell_st):

I know... the method I used will get the answer for you...

OpenStudy (anonymous):

i got A is that correct? @campbell_st

OpenStudy (campbell_st):

well what value do you get for the integer x as the 2nd integer is x + 2

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