The sum of the reciprocals of two consecutive even integers is 7/24. Write an equation that can be used to find the two integers. Find the two integers.
@DemolisionWolf
start with the basics the consecutive even integers are x and x + 2 their reciprocals are \[\frac{1}{x} ...and.... \frac{1}{x + 2}\] then using the sum you have \[\frac{1}{x} + \frac{1}{x + 2} = \frac{7}{24}\] so this requires a common denominator on the left \[\frac{(x +2) + x}{x(x+2)} = \frac{7}{24}\] simplify and cross multiply and you get \[24(2x + 2) = 7(x^2 + 2)\] which becomes \[7x^2 - 34x -48 = 0\] so the quadratic... for x.... and you'll have the value for x.... I'd recommend the general quadratic formula... only use the answer for the positive even integer... hope it helps
i put the wrong attachment :O @campbell_st its this one
I know... the method I used will get the answer for you...
i got A is that correct? @campbell_st
well what value do you get for the integer x as the 2nd integer is x + 2
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