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How do I integrate this? Please help. 2u/(1+u)
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\[\frac{ 2u }{ 1+u } du\]
I have tried the integration by parts formula but can't get the answer. -_-
Naw that won't work, you'll have to split it.
How?
Never mind, just do long division, you'll get this. \[2\int\limits \left( 1 -\frac{ 1 }{ u+1 } \right)du\]
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Yeah split it now, after you do long division.
\[2 \int\limits 1 du - 2 \int\limits \frac{ 1 }{ u+1 }du \]
x = u+1 dx = du
So I'll get \[2(u-\ln (1+u))\]?
+C but yup :)
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Thank you so much. >_<
Np :P
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