Question

Help pls.

Solve. x^2/4 + 4X = 0

A. {0, –16}

B. {–4, 0, 4}

C. {0, –4}

D. {0, 16}

Answer 1

Any ideas?

Answer 2

honestly no.

Answer 3

I this the equation you want to solve? $$\Huge \frac{x^2}{4} + 4x = 0$$

Answer 4

yes

Answer 5

Factor x and the constant terms

Answer 6

When you solve equations you are looking for values of x that will make the equation a true statement, right @Homeschooler1 ?

Answer 7

yes.

Answer 8

You could also use complete the square

Answer 9

Let's multiply both sides by 4 to get rid or the 1/4 Ok?

Answer 10

ok

Answer 11

$$\Huge \frac{x^2}{4} + 4x = 0$$ $$\Huge 4( \frac {x^2}{4} + 4x) = 4*0$$ $$\Huge {x^2} + 16x = 0$$

Answer 12

okay. Then cant we use the Zero Product Property?

Answer 13

Yes, we will after the next step...can you tell me what that is?

Answer 14

subtracting the 16x?

Answer 15

Nope. Hint: we need to turn that equation into a product first to use the Zero product property.

Answer 16

....

Answer 17

Any other ideas? (like factoring?) :-)

Answer 18

umm factoring out the equation?

Answer 19

Yes, see the common factor of x in the two terms?

Answer 20

$$\Huge {x^2} + 16x = 0$$

Answer 21

yeah

Answer 22

So, factor it out.

Answer 23

$$\Huge x(x + 16) = 0$$

Answer 24

ok

Answer 25

Now, as you said, use the zero product property to find the values of x that will turn that equation into a true statement :-)

Answer 26

so it would be {0, -16} ?

Answer 27

Thank you for all your help!!

Answer 28

You are correct. Thanks for asking.