Question

Can someone help me >> Fan & Metals

Answer 1

I can try

Answer 2

Thats good enough for me. C:

Answer 3

okay so the easiest way to solve for this is to plug in values of n into the equations and see if they correspond to they're appropriate f(n)

we know that the coefficient for n = 1 is f(n) = 16
so the coefficient in front of the equation needs to be 16, not 32, that rules out B and D

Answer 4

i dont know this one either /.\

Answer 5

so to decide between A and C, we can plug in the values for n. when n = 1, we want the exponent of 0.5 to be 0, so that it resolves to 1, and the coefficient 16 doesn't change. this can be done by subtracting 1 from the exponent as it does in answer A

Answer 6

a

Answer 7

When you are done, if you like I can give you a general approach for how to do these?

Answer 8

i think i get that one now, could one of you help with 2 more questions?

Answer 9

for your second question, your coefficient are less that 1, which means as you exponentially grow your value of x, g(x) will be getting large and p(x) will be getting smaller approaching 0. neither of their intercepts are the same

Answer 10

\[\sqrt{50} = 5\sqrt{2} \rightarrow 5\sqrt{2} + \sqrt{2} = 6\sqrt{2}\]


for the third question

Answer 11

fourth question \[\sqrt[3]{2} = 2^{\frac{ 1 }{ 3}}\]
\[2^{\frac{ 1 }{ 3}}* 2^{\frac{1}{2}} = 2^{\frac{1}{6}}\]

Answer 12

so the second one was d?

Answer 13

correct

Answer 14

would this be graph A?

Answer 15

yes!

Answer 16

one more?

Answer 17

i think its C

Answer 18

thank you so much, im ging to be busy all weekend with celebrating my birthday and i need to pass this lesson!