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Mathematics 53 Online
OpenStudy (anonymous):

The height, in meters, of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 3 to t = 6 represent? The coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds. The coin falls down with an average speed of 14.7 meters per second from 3 seconds to 6 seconds. The coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.

OpenStudy (anonymous):

The coin travels an average distance of 14.7 meter

OpenStudy (anonymous):

@ooops

OpenStudy (anonymous):

if plugging 3 and 6 to the equation, what do you have for d(3) and d(6)?

OpenStudy (anonymous):

44.1 for d(3)

OpenStudy (anonymous):

d(6)=176.4

OpenStudy (anonymous):

@ooops you there?

OpenStudy (anonymous):

something is wrong !! I posted, I saw my comment and then it disappeared. Magic!!

OpenStudy (anonymous):

:P hmm

OpenStudy (anonymous):

\(\dfrac{d(6)-d(3)}{6-3}\)

OpenStudy (anonymous):

maybe you typoed and some program marked ity as innapropriate and it s=dissapeared

OpenStudy (anonymous):

so d3/3

OpenStudy (anonymous):

That's the average change of distance in 3 seconds

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

so? the answer is?

OpenStudy (anonymous):

A?

OpenStudy (anonymous):

nope, the last one, because distance/ time = velocity

OpenStudy (anonymous):

okay thx

OpenStudy (anonymous):

no isnt direction/time velocity?

OpenStudy (anonymous):

i thought d/t was speed

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

the entire D The coin travels an average distance of 14.7 meters is per second from 3 seconds to 6 seconds.

OpenStudy (anonymous):

@OOOPS

OpenStudy (anonymous):

how about this option? The coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.

OpenStudy (anonymous):

your d(t) is the equation of distance, not velocity

OpenStudy (anonymous):

still not get?

OpenStudy (anonymous):

i get it im checkin now

OpenStudy (anonymous):

wait i just clicked wrong my first try

OpenStudy (anonymous):

the equation is -b/2a right?

OpenStudy (anonymous):

What are you talking about? -b/2a is the last question, not this. This question is about distance and velocity. If they said so, click A. I don't know why but just 2 of them are correct. To me, it's the last one. Maybe, I am wrong

OpenStudy (anonymous):

ik im redoing the assesment and i got the same question different equations i was jsut making sure

OpenStudy (anonymous):

i misclicked the first on i think the last 1 is right

OpenStudy (anonymous):

thx i have one morwe Q

OpenStudy (anonymous):

thx @ooops

OpenStudy (anonymous):

@OOOPS what was the anwser to the first question a b or c?

OpenStudy (anonymous):

@OOOPS

OpenStudy (anonymous):

what??? this post was posted 3 months ago, right? how it still works???

OpenStudy (anonymous):

@OOOPS with the school we do, they circulate questions. Thanks for the help you didnt mean to give XD you helped check my work

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