A company sells candy bars. The table below shows the total weight of a box with 1,2,3, and 4 candy bars Number of candy bars in box| Total weight ________________________________________ 1 | 9.5 2 |15.5 3 |21.5 4 |27.5
@ranga
So what is the question?
I am supposed to write an algebraic rule that can be used to determine the total weight of the box for any number of candy bars.
Well since you add 6 each time you add a candy bar, the algebraic equation would be 3.5 + 6x = Y(Total weight of the box) Where x is the number of candy bars. You get 3.5 by finding the Y-intercept, subtracting 6 from (1, 9.5) to get (0,3.5). The y-intercept symbolizes the weight of the box.
Ok, thanks
@jim_thompson5910
How would I find the Y intercept?
From a graph? and what 2 points would I use?
3.5 + 6x = y is the same as y = 6x + 3.5 That second equation is of the form y = mx+b slope: m = 6 y-intercept: b = 3.5 which is the point (0,3.5)
you can use any two points you want to graph the line
ok, Thanks!
How did you come up with 3.5?
do you know how to find the slope m = 6 ?
Slope is Rise/Run right?
How do you find the slope?
using the slope formula m = (y2 - y1)/(x2 - x1)
So, if I picked (1,3) and (2,3) that wouldn't work...
?
(1,3) (5,6) Won't work either
@zzr0ck3r
I can't figure this out @zzr0ck3r I picked 2 random points but they don't work
what is your question?
when he says pick pionts he does not mean pick random points, he means pick random x values plug that in to get the y value, now you have a point
but how did he get 3.5?
letting x = 0, we see y = 3.5 (0,3.5) is one point letting x = 1 we see y = 9.5 so (1,9.5) is another
How did he get 3.5 to write this equation y = 6x + 3.5
1 -> 9.5 2 -> 15.5 3-> 21.5 so its growing by 6 every time, so to find out what we get when x is zero (i.e. the y intercept) we take away 6 from 9.5 (because its 9.5 at 1)to get 3.5.
or take a point (1,9.5) you have y=6x+b plug in your point 9.5=6+b b=3.5
but to get the point (1,9.5) you needed the equation y = 6x + 3.5
So I will follow your first suggestion
Join our real-time social learning platform and learn together with your friends!