Question

3^-2+2^2/4^-2/2^-2 evaluate

Answer 1

\[3^{-2}+2^{-2}\div 4^{-2} + 2^{-2}\]

Answer 2

sorry 3^-2 + 2^2

Answer 3

\[\large \frac{3^{-2}+2^2}{4^{-2}+2^{-2}}\]?

Answer 4

\[\frac{ 3^{-2}+2^{-2} }{ 4^{-2}+2^{-2} }\]

Answer 5

yeah! :) @satellite73

Answer 6

there is not short cut here
you have to compute each number separately

Answer 7

for example
\[3^{-2}=\frac{1}{3^2}=\frac{1}{9}\]

Answer 8

\[\huge \frac{ \frac{ 1 }{ 3^2 }+\frac{ 1 }{ 2^2 } }{ \frac{ 1 }{ 4^2 }+\frac{ 1 }{ 2^2 } }\]

Answer 9

\[2^2=4\\
4^{-2}=\frac{1}{4^2}=\frac{1}{16}\\
2^{-2}=\frac{1}{4}\]

Answer 10

Should be pretty simple from there :P

Answer 11

@iambatman i think i might be \[\huge \frac{ \frac{ 1 }{ 3^2 }+2^2 }{ \frac{ 1 }{ 4^2 }+\frac{ 1 }{ 2^2 } }\]

Answer 12

do i just divide them now?

Answer 13

Ohhhh yeah nice catch satellite

Answer 14

you have to do the annoying arithmetic top and bottom separately, then divide by multiplying by the reciprocal of the denominator

Answer 15

sorry what do you mean by top and bottom seperatly?

Answer 16

\[\huge \frac{ \frac{ a }{ b } }{ \frac{ c }{ d } } = \frac{ ad }{ bc }\]

Answer 17

for example
\[\frac{1}{9}+4=\frac{37}{9}\] that is the top

Answer 18

i got 592/45 as my final answer is that right ? @satellite73 @iambatman