Find the electric field intensity at a point O due to straight line charge of linear charge density = $\lambda$ .

@hartnn @ganeshie8

Question

Find the electric field intensity at a point O due to straight line charge of linear charge density = $\lambda$ .

@hartnn @ganeshie8

mathslover · Answer

attachment

mathslover · Answer

Give me one minute and I will post what I did yet.

anonymous · Answer

those are the only variables? alpha, beta and lamda ?!

mathslover · Answer

Lambda is the linear charge density. Alpha , beta are the angles (variables).

mathslover · Answer

Okay, so here is what I have done so far.

mathslover · Answer

@hartnn - Will you please check if I am right till now?

anonymous · Answer

yes correct.. .. Continue

mathslover · Answer

But the book has something else ! 

It says, dE = $\cfrac{k \lambda }{a} d\theta$

anonymous · Answer

ermm.. i think its directly using the result of Field due to infinitely long line of charge which is
$$E = \frac{k \lambda }{a}$$

but i wonder.. how that is included here :D.. i think u can do it from ground zero though.. the way you started..

mathslover · Answer

Well, I tried to do it several times and I got the same which I showed. But the book says different!

anonymous · Answer

well what is the final solution!?

did you try evaluating E field using ur method? what do you get?!

mathslover · Answer

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