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Mathematics 16 Online
OpenStudy (elisaneedshelp):

Please i need help! Sorry for not writing out the question. I hope the picture can be seen. Please ill medal and fan!

OpenStudy (elisaneedshelp):

OpenStudy (elisaneedshelp):

and my teacher also wants like a list of what i need to solve the problem and then traps that could be in the problem :/ please

OpenStudy (elisaneedshelp):

@ganeshie8 sorry to bother but there is no1 else who i know can help me right now i hope you can

OpenStudy (elisaneedshelp):

@iPwnBunnies somebody

OpenStudy (elisaneedshelp):

@RoseDryer hopefully you can help me

OpenStudy (anonymous):

You're going to use the distance formula \[\large d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]

OpenStudy (anonymous):

If STUV is congruent to LMNP So SU is congruent to LN and TV is congruent to MP so we will use the points for LN and MP

OpenStudy (elisaneedshelp):

so like i do \[d=\sqrt{(2-0)^{2}}+(4-0)^{2}\]

OpenStudy (elisaneedshelp):

and then i do the same with the other points

OpenStudy (ipwnbunnies):

You used the wrong point. You're trying to find the distance between points L and N. Plus, the square root is over the entire thing.

OpenStudy (elisaneedshelp):

Well im just using that as an example and yeah but i didnt know how to put it on here

OpenStudy (anonymous):

Let's find SU first L=(0,0) N=(8,6) \[d=\sqrt{(8-0)^2+(6-0)^2}\] \[d=\sqrt{8^2+6^2}\] \[d=\sqrt{64+36}\] \[d=\sqrt{100}\] \[d=10\] Now we'll find the other TV M = (2,4) P = (6,2) \[d=\sqrt{(6-2)^2+(2-4)^2}\] \[d=\sqrt{4^2+-2^2}\] \[d=\sqrt{16+4}\] \[d=\sqrt{20}\] To figure out the length do this |dw:1400340222275:dw|

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