Please help me!!! Two opposite sides of a square with length x are increased by 3 units each and the other two opposite sides are decreased by 3 units each. If the area of the resulting rectangle is 27 unit2, what would be the width of the rectangle?
1) It depends on which pair of sides you are calling the width. 2) Area of square with sides of length x, Area = x*x 3) Area of defined rectangle, Area = (x+3)*(x-3) = 27 Where does that leave us?
You solve for x and you will get the answer.
(x+3)*(x-3) = 27 (6+3)*(6-3) = 27 (9)*(3) = 27 Looks like the longest side of the rectangle would be 9 units.
Wow! Of course! Just pull it out of your hat. Wave your magic wand and it happens! (x+3)*(x-3) = 27 x^2 - 9 = 27 x^2 - 36 = 0 (x+6)(x-6) = 0 x = -6 or x = 6 As this is a real rectangle, x = -6 is no good. Throw it out! x = 6
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