What are the asymptotes of ↓↓↓↓

Question

anonymous · Answer

$$5(x-1)^2+4(y+2)^2=20$$

amistre64 · Answer

a slope of b/a  for a line thru the center ....

amistre64 · Answer

but that looks to be an ellipse?

amistre64 · Answer

if its a hyperbola, then + to - for a typo

anonymous · Answer

This is right out of my text book?

amistre64 · Answer

then i was right, you mis typed it

anonymous · Answer

oh i see what i did oops....

amistre64 · Answer

algebra it into the standard form:$$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$$

amistre64 · Answer

then asymptotes are:$$y=\pm\frac ba(x-h)+k$$

anonymous · Answer

Thank you I'll post what I got in a min!

anonymous · Answer

$$\frac{ (x-1)^2}{ 4} -\frac{ (y+2)^2 }{ 5 }$$

amistre64 · Answer

so far so good

amistre64 · Answer

b^2 = 5; b=?
a^2 = 4; a=?

anonymous · Answer

b=2.2361, a=2

amistre64 · Answer

b = sqrt(5)  no need to approximate unless told to

so what we have is ... pulling the xy parts to fit

$$(y+2) =\pm\frac{\sqrt5}{2}(x-1)$$
$$y =\pm\frac{\sqrt5}{2}(x-1)-2$$

anonymous · Answer

Okay and now how do I solve?

amistre64 · Answer

that is the solution ... just work it into whatever format they want you to:  maybe y=mx+b ??

anonymous · Answer

oh okay thank you!

amistre64 · Answer

youre welcome

nipunmalhotra93 · Answer

@amistre64 I know that your answer is correct but I just wanna ask: how is it possible for an ellipse to have an asymptote?

amistre64 · Answer

its not :)  which led me to believe it was a typing error.

amistre64 · Answer

i should amend that as:  ive never come across it happpening

nipunmalhotra93 · Answer

oops.. I didn't read all the messages above lol... anyways thanks :D (Y)