Math Questions!!
you know the formula for n'th term of geometric sequence ?
Yes
let the first term be 64 then, and +7 to find 14, and -6 to find 1
r = common ratio = -2 is given if you plug in n =7, you'll get expression for a7 and you already know a7 = 64
-2 assuming typos
a1 is unknown \(\large a_n = a_1 r^{n-1} \\ \large 64 = a_1 (-2)^{7-1}\)
\[b_1=64(-2)^{1-1}\] \[b_m=64(-2)^{m-1}\]
Two different numbers.. :I
when for m=n+6, n=m-6
which 2 different numbers ?
2 different approaches is all :) same structure
You wrote al is unknown but amistree wrote n is unknown...
follow either one of us....if you see all comments, you will get confused...
where a sequence starts is immaterial, as the distances between terms does not change
with both the approaches, you will get the same answer
I see, thank you.
I have one more question. Do you mind? :I
ask
(64) a = 1, 2, 3, 4, 5, 6, 7, 8, 9,10,11,12,13,14 b = -5,-4,-3,-2,-1, 0, 1, 2, 3, 4, 5, 6, 7, 8
negative value of 'n' is not so conventional...
letting the starting point be 0 i find more useful: a1 = b(-6) a(14) = b7 bn = 64(-2)^n
also , -4,12, 36.. is not a geometric sequence at all check the question ? is it -36 ?
Oh yes. :I Sorry
find the common ratio 'r' first if |r|<1 , then use the sum formula \(\Large S_n = a_1 \dfrac{r^n-1}{r-1}\) a1 = 1st term = -4 if |r| > 1, then the series diverges and there will be no sum
r = -3 a1 = -4 n =7 plug these in
\(S_7 = (-4) \dfrac{(-3)^7-1}{(-3-1)}\) calculate that ^
-2188?
thats correct :)
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