You are standing in front of a flat large mirror. As you step 1.0 m farther from the mirror, the distance between you and your image changes by __________. (Points : 1) 0 m 1.0 m 2.0 m 0.5 m
A flat mirror has an infinite radius of curvature and therefore a focal length of infinity. If we plug that into the thin lens equation we get:\[\frac{ 1 }{s _{i} }=\frac{ 1 }{ s _{o} }+\frac{ 1 }{ \infty }=\frac{ 1 }{s _{o} }+0\]That means that si--the image distance--has to equal so--the object distance. That also means they both have the same sign and are therefore on the same side of the mirror. So given that, what do you think the answer is?
is it 2.0m?
Yes, it's two meter. I should have stated that si=-so. They don't have same sign.
Okay, awesome. Thanks!
The diagram illustrates a convex mirror, with F and F´ at a distance of one focal length f from the mirror, and with C as the center of the sphere that describes the mirror's shape. In what direction is the ray drawn to find the reflected image in the mirror? the direction from P through F parallel to the principal axis perpendicular to the principal axis along the line from F´ to P
@PsiSquared
Here's how the ray would be traced. Note the real ray is reflected according to the law of reflection. The dashed line represents the virtual ray.
So would the answer be A?
Yes, the line is drawn between P and F. So, does that make the image virtual or real?
It makes the image real, correct? @PsiSquared
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