How many grams of sodium metal are needed to react completely with 25.8 liters of chlorine gas at 293 Kelvin and 1.30 atmospheres?
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OpenStudy (epicteatime):
can people tell me how 2 get moles?
OpenStudy (epicteatime):
@iPwnBunnies @ParthKohli
OpenStudy (epicteatime):
@aaronq
OpenStudy (epicteatime):
@AccessDenied
OpenStudy (epicteatime):
@jigglypuff314
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OpenStudy (epicteatime):
can you tell me how to get moles?
OpenStudy (aaronq):
use the ideal gas equation, PV=nRT, to get moles, n.
OpenStudy (epicteatime):
so?
OpenStudy (epicteatime):
how do i do it?
OpenStudy (epicteatime):
n=PV*RT?
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OpenStudy (epicteatime):
or divide...;(
OpenStudy (aaronq):
nope, divide n=PV/RT
OpenStudy (epicteatime):
oh
OpenStudy (epicteatime):
P=pressure, V=volume, and R=constant, and T=temp. right?
OpenStudy (aaronq):
correct, T needs to be in Kelvin, btw.
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OpenStudy (epicteatime):
oh?
OpenStudy (epicteatime):
n=1.3 x 25.8/0.0821 x 293?
OpenStudy (epicteatime):
is it this?
OpenStudy (aaronq):
yeah (i just noticed the temp is already given in Kelvin lol)
OpenStudy (epicteatime):
lol
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OpenStudy (epicteatime):
so is that correct?
OpenStudy (aaronq):
Yeah, now to find the grams of sodium, you need to find the moles of sodium first, then convert.
OpenStudy (epicteatime):
1.294g/mol.
OpenStudy (epicteatime):
whoops, 1.394
OpenStudy (epicteatime):
right?
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OpenStudy (aaronq):
yeah, but the units aren't "g/mol", it's just moles
OpenStudy (epicteatime):
oh
OpenStudy (epicteatime):
so i just do the thing, except i add n instead of =n right?
OpenStudy (aaronq):
im not sure i follow
OpenStudy (epicteatime):
?
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OpenStudy (epicteatime):
what do i do after i find mole?
OpenStudy (aaronq):
you need to use the molar ratio between them, so write and balance the chemical equation for the process
OpenStudy (epicteatime):
i know the balanced equation 2 Na (s) + Cl2 (g) → 2 NaCl (s)
OpenStudy (epicteatime):
i think its that, it was already given
OpenStudy (aaronq):
yeah that's it.
so now, make a ratio of the moles with the coefficients:
\(\dfrac{n_{Na}}{2}=\dfrac{n_{Cl_2}}{1}\)
plug in moles of what you know, then solve
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OpenStudy (epicteatime):
ok...
OpenStudy (epicteatime):
ummm, 1.394Na/2=1.394Cl^2/1?
OpenStudy (epicteatime):
which is 0.697=1.394
OpenStudy (aaronq):
you only know the moles of \(Cl_2\), right? (you found this above)
this \(n_{Cl_2}\) is just a symbol for that.
so it's \(\dfrac{n_{Na}}{2}=\dfrac{1.394}{1}\rightarrow n_{Na}=\dfrac{1.394*2}{1}\)
OpenStudy (epicteatime):
yeah
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OpenStudy (epicteatime):
oh
OpenStudy (epicteatime):
2.788Na
OpenStudy (aaronq):
yeah so that's moles, 2.788 moles of sodium metal
now convert the moles to grams, use \(n=\dfrac{m}{M}\)
OpenStudy (epicteatime):
ok
OpenStudy (epicteatime):
1.394=whats m/M?
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OpenStudy (aaronq):
m = mass in grams (what you're looking for)
M= molar mass (of sodium)
OpenStudy (epicteatime):
ok
OpenStudy (epicteatime):
1.394=m/2.788
OpenStudy (epicteatime):
m=2.788 x 1.394?
OpenStudy (epicteatime):
m=3.89
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OpenStudy (aaronq):
the molar mass of sodium is 22.9898 g/mol
OpenStudy (aaronq):
you can find this on a periodic table
OpenStudy (epicteatime):
oh
OpenStudy (epicteatime):
the atomic number?
OpenStudy (epicteatime):
well, the number below
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OpenStudy (aaronq):
nope, the atomic number is only the number of protons
OpenStudy (aaronq):
yeah, it's called atomic mass (or molar mass because it's the mass of 1 mole of that substance)
OpenStudy (epicteatime):
ok, so now
OpenStudy (epicteatime):
1.395=22.989/2.788
OpenStudy (aaronq):
hm you're confusing the variables.
n=moles = 2.788 moles
m=mass (in grams) = x
M= molar mass = 22.9898 g/mol
the formula is: \(n=\dfrac{m}{M}\)
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OpenStudy (epicteatime):
ohhhh
OpenStudy (epicteatime):
2.788=x/22.9898
OpenStudy (epicteatime):
so, x=2.788 x 22.9898?
OpenStudy (aaronq):
yes
OpenStudy (epicteatime):
x=64.1
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OpenStudy (aaronq):
\(\checkmark \)
OpenStudy (aaronq):
dont forget the units
OpenStudy (epicteatime):
yay! 64.1g/mol
OpenStudy (aaronq):
nope, just grams. remember this is the mass, not the molar mass