Question

Please help me (Please)

Answer 1

Find the values of function 2x^3 -15x^2 +36x +11 at the points of maximum and minimum

Answer 2

@AravindG

Answer 3

I'm assuming you're in calculus and you know about derivatives?

Answer 4

Yes i calculated the first derivative and i will tell you what i did wait a sec

Answer 5

First derivative:- 6x^2 - 30x +36
On dividing by 6
x^2 -5x +6
(x-3)(x-2)=0
x=3 or 2

Second derivative
2x-5

For x=3
2(3) -5
=1
1>0 So there lies a minima

For x =2
2(2) - 5
4-5 =-1

-1<0 ------> so there lies a maxima


What should i do after that

Answer 6

x = 3, x = 2 are the critical values

at x = 3, the second derivative is positive (so the region is concave up ---> local min)

now you plug in x = 3 back into the original function to get the y coordinate of the point (3, y). This point is where the local min is. The y value of this point is the local min value.

Answer 7

the same can be said about x = 2, but since the second derivative is negative, it's at the local max

Answer 8

I see so these are the points at which the values lie , I get the intuition now
Thanks buddy :)

Answer 9

you're welcome