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Mathematics 8 Online
OpenStudy (breathlessreaper):

Please help mee D: ???

OpenStudy (breathlessreaper):

The price of products may increase due to inflation and decrease due to depreciation. Derek is studying the change in the price of two products, A and B, over time. The price f(x), in dollars, of product A after x years is represented by the function below. f(x) = 72(1.25)x Part A: Is the price of product A increasing or decreasing and by what percentage per year? Justify your answer. Part B: The table below shows the price f(t), in dollars, of product B after t years: t (number of years) 1 2 3 4 f(t) (price in dollars) 65 84.5 109.85 142.81 Which product recorded a greater percentage change in price over the previous year? Justify your answer.

OpenStudy (breathlessreaper):

@undeadknight26 @jim_thompson5910

jimthompson5910 (jim_thompson5910):

hint: rewrite 1.25 into the form 1+r

OpenStudy (breathlessreaper):

so 1+1.25=2.25?

jimthompson5910 (jim_thompson5910):

1.25 = 1+r solve for r

OpenStudy (breathlessreaper):

I dont knoww

OpenStudy (breathlessreaper):

1/4?

jimthompson5910 (jim_thompson5910):

1/4 = 0.25, so yeah

jimthompson5910 (jim_thompson5910):

r = 0.25

jimthompson5910 (jim_thompson5910):

since r is positive, we have 25% growth

jimthompson5910 (jim_thompson5910):

so the inflation rate is 25% (the price increases by 25% each year)

OpenStudy (breathlessreaper):

Okay. what about Part B: The table below shows the price f(t), in dollars, of product B after t years:

jimthompson5910 (jim_thompson5910):

what's the difference in 65 and 84.5

OpenStudy (breathlessreaper):

19.5?

jimthompson5910 (jim_thompson5910):

divide that by the first number 65

OpenStudy (breathlessreaper):

.30

jimthompson5910 (jim_thompson5910):

do the same for 84.5 and 109.85

OpenStudy (breathlessreaper):

i got 0 o.o

OpenStudy (breathlessreaper):

whoops, i did something wrong

OpenStudy (breathlessreaper):

yeah i got .30 again

jimthompson5910 (jim_thompson5910):

how about from 109.85 to142.81

OpenStudy (breathlessreaper):

.30

jimthompson5910 (jim_thompson5910):

so every year, product B is increasing in price by 30%

OpenStudy (breathlessreaper):

Thank you C: can you help with one more? Belinda wants to invest $1000. The table below shows the value of her investment under two different options for two different years: Number of years 1 2 3 Option 1 (amount in dollars) 1100 1200 1300 Option 2 (amount in dollars) 1100 1210 1331 Part A: What type of function, linear or exponential, can be used to describe the value of the investment after a fixed number of years using option 1 and option 2? Explain your answer. Part B: Write one function for each option to describe the value of the investment f(n), in dollars, after n years. Part C: Belinda wants to invest in an option that would help to increase her investment value by the greatest amount in 20 years. Will there be any significant difference in the value of Belinda's investment after 20 years if she uses option 2 over option 1? Explain your answer, and show the investment value after 20 years for each option.

jimthompson5910 (jim_thompson5910):

how far did you get?

OpenStudy (breathlessreaper):

Linear function right? I'm not quite sure what im doing.

jimthompson5910 (jim_thompson5910):

why do you think option 1 is linear?

OpenStudy (breathlessreaper):

Beacuse they only have a difference of 100?

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

so every year, the investment in option 1 is growing by $100

OpenStudy (breathlessreaper):

Yes.

OpenStudy (breathlessreaper):

in the second one, it grows by 110, then 121

jimthompson5910 (jim_thompson5910):

so that isn't linear

jimthompson5910 (jim_thompson5910):

what is the percentage change from year to year in option 2?

OpenStudy (breathlessreaper):

10%?

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

so that proves it's exponential

OpenStudy (breathlessreaper):

For Part B: Write one function for each option to describe the value of the investment f(n), in dollars, after n years. how would I write the function? f(n)=...

jimthompson5910 (jim_thompson5910):

what is the general form of linear equations?

OpenStudy (breathlessreaper):

y = mx + b

jimthompson5910 (jim_thompson5910):

m is the slope, ie rate of change

jimthompson5910 (jim_thompson5910):

it's how much it's changing each year, so m = ???

OpenStudy (breathlessreaper):

m=100

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

x = 1 (year 1) y = 1100 (amount of money in year 1) y = mx + b y = 100x + b ... plug in m = 100 1100 = 100*1 + b ... plug in x = 1, y = 1100 solve for b

OpenStudy (breathlessreaper):

b=1000?

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

so the linear equation is y = 100x + 1000 and replace y with f(n) and x with n to get f(n) = 100n + 1000

jimthompson5910 (jim_thompson5910):

you can now plug in any value of n you want to find out how much money there is for any year n

OpenStudy (breathlessreaper):

what about the second option? How would i write a function for that one?

jimthompson5910 (jim_thompson5910):

the general equation for exponential growth is f(n) = P*(1+r)^n P is the starting value r is the growth rate n is the number of years

OpenStudy (breathlessreaper):

Would i have to make more than one function?

jimthompson5910 (jim_thompson5910):

one function per option

jimthompson5910 (jim_thompson5910):

two options ----> two functions

OpenStudy (breathlessreaper):

I meant for the second option xDD i dont understand what i'd have to plug in

OpenStudy (breathlessreaper):

like... f(n) = 1100*(1+10%)^1 ??

jimthompson5910 (jim_thompson5910):

close

jimthompson5910 (jim_thompson5910):

what is the original amount she invested

OpenStudy (breathlessreaper):

Ohh, 1000

jimthompson5910 (jim_thompson5910):

P = 1000

jimthompson5910 (jim_thompson5910):

r = growth rate ---> r = 0.10 (10% = 0.10)

OpenStudy (breathlessreaper):

then n =... ? number of years, but what years xD

jimthompson5910 (jim_thompson5910):

you leave it as n for now if you wanted a certain year, say n = 1, you'd plug in n = 1

jimthompson5910 (jim_thompson5910):

so the function is f(n) = 1000(1.10)^n

OpenStudy (breathlessreaper):

So, for C i would plug in 20 for n??

jimthompson5910 (jim_thompson5910):

plugging in values of n will give you the amounts of money in the account

jimthompson5910 (jim_thompson5910):

correct, for each function

jimthompson5910 (jim_thompson5910):

then you compare the difference

OpenStudy (breathlessreaper):

I think i can do C by myself. I'll give you the answers i come up with and can you check them please? I want to see if i can get it

jimthompson5910 (jim_thompson5910):

go ahead

OpenStudy (breathlessreaper):

for the first option after 20 years she would get 3,000. For the second option she gets 6,727.5. The difference being 3,727.5. If she uses option two over option one, it would be a better choice because she would be getting the greatest amount in 20 years.

jimthompson5910 (jim_thompson5910):

very nice

OpenStudy (breathlessreaper):

Thank you for helping me, again c: I like it a lot better how you help me figure things out and you don't just give an answer without explanation.

jimthompson5910 (jim_thompson5910):

you're welcome and it's good to go through it like that (instead of just being given the answer)

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