Question

A tow truck exerts a net horizontal force of 1050 N on an 760-kilogram car. What is the acceleration of the car during this time? Show your work.

Answer 1

F=ma
=)1050N=760kg*a
=)a=~1.38m/s^2

Answer 2

As we know that \[F= ma \]

Answer 3

and \[a= \frac{ F }{ m }\] put the values of F and m in this equation

Answer 4

\[a= \frac{ 1050 }{ 760 } \]

Answer 5

1. 38 meter per second suquare is the answer.