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Help, pretty please? Which value of y forms the solution of the system defined by y = 11 x + 1 and 11 x + 12 y = 12?
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Start with 11x + 12y = 12 and plug in y = 11x + 1 11x + 12y = 12 11x + 12(11x + 1) = 12 ... replace every y with 11x + 1 now solve for x
Ahhhhh,it's one of those problem,s..
substitution is one way to do it, yes
elimination is another (you have to rearrange things though)
I got x=0 :/
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143x+12=12 x=0...
good, x = 0 is correct
now use this to find y
you can plug x = 0 into any equation with x,y in it y = 11x + 1 is the easiest to work with since y is already isolated
y = 11x + 1 y = 11(0) + 1 ... replace every x with 0 y = ??
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y=1
good
together, the solution is (0,1) ie x = 0, y = 1
much appreciated!
you're welcome
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