Question

Binding energy problem

The mass of a K-40 nucleus is 37 216 MeV c–2. Determine the binding energy per nucleon
of K-40.

Proton number of K is 19.

Answer 1

@ganeshie8

Answer 2

@AravindG

Answer 3

We know that \[E=mc ^{2}\]

Answer 4

Formula is.. E =\[ \Delta m c ^{2}\]

Answer 5

and Delta "m" is mass defect. ANd \[\Delta m = Z m _{p} c ^{2} + (A - Z) m _{nucleus} c ^{2} - m c ^{2}\]

Answer 6

Where Z is the total number of protons in the nucleus, \[m _{p}\] is the mass of a proton. then Z\[m _{p}\]c is the total mass of all protons.

Answer 7

(A-Z) is the total number of neutrons. and \[m_{nucleus }\] is the experimentally measured mass of the entire nucleus.

Answer 8

Brother now do it by putting the values in that equation.

Answer 9

hmmm i dont understnd

Answer 10

Had not you read its basics brother??

Answer 11

@sre i think i don't deserve this medal in this question, because, i can't explain it as much as, @thushananth01 understand it... perhaps my poor skills... :(

Answer 12

@IhteshamMalik i think your answer is right .

Answer 13

Let see... may be some one else give the more athentic solution for this question...

Answer 14

"So mass defect Delta m = 40-39.974221 = 0.025779 amu "

that is wrong brother

Answer 15

In first method its wrong @Mashy but the 2nd formulation is correct..

Answer 16

Perhaps it should be (A -Z) x mass of neutron

Answer 17

(A - Z) x mass of neutron x c^2