Question

.

Answer 1

\(\Large\color{blue}{ \bf (a-b)(a+b) =a^2-b^2 }\)

Answer 2

Then apply the \(\Large\color{red}{ \bf sin^2x+cos^2x=1 }\)

Answer 3

a is 1 and b is sin(x)

Answer 4

so
1 - sin(x)
How do I apply this to sin^2x + cos^2x = 1
?

Answer 5

not sin(x), but sin²x

Answer 6

And then,

\(\Large\color{red}{ \bf sin^2x+cos^2x=1 }\)
\(\Large\color{blue}{ \bf ~-sin^2x~~~~~~~~~~~-sin^2x }\)

\(\Large\color{red}{ \bf cos^2x=1-sin^2x }\)

Answer 7

@SolomonZelman

Answer 8

I told you all the steps.

Answer 9

Then how do I find the answer?

Answer 10

I am telling you,

Expand \(\Large\color{red}{ \bf (1-sin~x)(1+sin~x) }\) using (a+b)(a-b)=a²-b²

Then apply the \(\Large\color{red}{ \bf cos^2x=1-sin^2x }\)

Answer 11

it will equal to (cos x)^2

Answer 12

Yeah :)

Answer 13

Thanks!

Answer 14

Anytime !