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OpenStudy (anonymous):
Yes it would:
Cl2 + 2I- ---> I2 + 2 Cl-
Cl2 + 2e- ---> 2 Cl- E=1.36
I2 + 2 e- ----> 2 I- E=0.54
Since the potential of the Cl couple is higher the I- can reduce Cl2
OpenStudy (anonymous):
what does E mean?
OpenStudy (anonymous):
@Butchy ?
OpenStudy (anonymous):
Sorry I wasn't paying attention , E is standard electrode potential
OpenStudy (anonymous):
:D
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OpenStudy (anonymous):
but we didn't study that in my class
OpenStudy (anonymous):
I think the answer is has to do with activity series chart
OpenStudy (anonymous):
but I'm not sure how to answer it
OpenStudy (anonymous):
Have you hear of Reduction potential ? ( not so sure of the term since english isn't my primary langage)
OpenStudy (anonymous):
We studied the activity series in my class
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OpenStudy (anonymous):
Then you should have some kind of charts, the higher up the charts the stronger the oxydant agent is Chlorine should be higher than iode so that explains why Cl2 would be reduced