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Mathematics 20 Online
OpenStudy (hang254):

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in standard form. 5, -3, and -1 + 2i

OpenStudy (hang254):

@ajprincess @SolomonZelman

OpenStudy (kinggeorge):

Do you remember what you have to do when you have an imaginary root (such as \(-1+2i\))?

OpenStudy (hang254):

not really, sorry

OpenStudy (kinggeorge):

No problem. It's fairly simple. All it is, is when you have an imaginary root (such as \(-1+2i\)), you have to have the complex conjugate as a root as well. In this case, the complex conjugate is \(-1-2i\). So your polynomial will have 4 roots. Those will be\[5,\;-3,\;-1+2i,\;-1-2i.\]

OpenStudy (kinggeorge):

Next, we need to find the actual polynomial. To do this, multiply the 4 factors \(x-r\) where \(r\) is one of your roots. So in factored form, the polynomial will be\[(x-5)(x+3)(x-(-1+2i))(x-(-1-2i)).\]All you have to do is multiply these together one by one. Hint: Multiply \((x-(-1+2i))(x-(-1-2i))\) first.

OpenStudy (kinggeorge):

It'll take a bit of work to do this final step. Let me know what you get at the end.

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