please help, arrange the following from most to least oxidized:
I.CH3CH3
II.CH3CH2-OH
O
||
III. CH3CH

please explain how you determine which is least/most oxidized... or link me to a helpful website.

Question

please help, arrange the following from most to least oxidized:
I.CH3CH3
II.CH3CH2-OH
             O
             ||
III.   CH3CH

please explain how you determine which is least/most oxidized... or link me to a helpful website.

anonymous · Answer

ester /acid is more oxidized than ketones and aldehyde which is more than alcohol which is more than alkane 
Count the number of oxydation in the case of alkane it's obliviously the less oxidized
for alcohol the Carbon bearing the -OH is +1 since O is -2 and H +1
The one bearing the Ketone is +2 since there is no H anymore
if you have COOH the Carbon is +3
So  III<II<I

anonymous · Answer

thanks so much! (: