Question

evaluate tan pi/12

Answer 1

\[2-\sqrt{3} \]

Answer 2

pi/12 = 15 degrees
Ust the half angle formula below where alpha is 30 degrees.\[\tan \left(\frac{\alpha }{2}\right)=\frac{1-\cos (\alpha )}{\sin (\alpha )} \]

Answer 3

can you break it down as to how you got that answer

Answer 4

Set alpha in the tangent expression to 30 degrees. 30/2 = 15 degrees.
Replace each alpha in the RHS of the equation with 30 degrees and then evaluate the result.
\[\frac{1-\cos (30 {}^{\circ})}{\sin (30 {}^{\circ})} \]\[\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}} \]\[2 \left(1-\frac{\sqrt{3}}{2}\right) \]\[2-\sqrt{3} \]

Answer 5

thank you

Answer 6

Your welcome.