What is the 7th term of the geometric sequence where a1 = 1024 and a3 = 64?
\(\large\color{blue}{ \bf a_{1} \times r=a_{2} }\) and \(\large\color{blue}{ \bf a_{3} \div r=a_{2} }\) knowing that they are both equal to a2, (and knowing a1 and a3) can you find the r ?
1,024 x r = a_2 64/r = a_2 So... my guess is to divide 1,024 by 64 So the answer is 0.0625
We can set the equations as, \(\large\color{blue}{ \bf a_1 \times r = a_3 \div r }\) because each side gives the value of the second term.
Thank you again :) I just need to be shown the formula and see what matches to what and I think I'm set! :) Could you help me with one last question?
\(\large\color{blue}{ \bf 2014 \times r = 64 \div r }\) \(\large\color{blue}{ \bf 2014 \times r^2 = 64 }\) \(\large\color{blue}{ \bf r^2 = \frac{64}{2014} }\)
So the ratio is the square root of that fraction... I don't like dealing with not-perfect squares -:(
oh! So that wasn't the correct answer?
https://www.google.com/#q=64+divided+by+2014 and then square root of that, or you can work with the exact value. Whatever you prefer.
ok thank you :) you're a lifesaver!
Lets work with an exact value. But before can you answer one question ?
Do you understand why (ready? pay attention!!! ) are there going to be different ratios, and why don't we have to worry about this (and we can just work with the positive ratio) ?
2 different ratios...
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