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evaluate sec(sin^-1 4/5)
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Suppose \(\theta=\sin^{-1}\dfrac{4}{5}\), so that \(\sin\theta=\dfrac{4}{5}\). This gives you a triangle: |dw:1400440742709:dw| What's the length of the missing side? If \(\theta\) is the angle on the left, what would its secant be?
sin of -4/5
Um, what?
Guessing I am not really that good with this trig stuff
|dw:1400442628497:dw| From the Pythagorean theorem, you get \[\begin{align*}x^2+4^2&=5^2\\ x^2&=25-16\\ x^2&=9\\ x&=3 \end{align*}\] So if \(\cos\theta=\dfrac{\text{adjacent}}{\text{hypotenuse}}\) and \(\sec\theta=\dfrac{1}{\cos\theta}\), what do you get?
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5/3
Correct
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