Elementary charge, e = 1.6x10-19 C.
Ni nuclear radius = 4x10-15 m. Ni atomic number = 28. Ni mass = 9.7x10-26 kg.

a) An accelerator accelerates Ni10+ ions through a total potential difference of 6.4 MV. What is the kinetic energy of an ion once it leaves the accelerator?

Question

Elementary charge, e = 1.6x10-19 C.
Ni nuclear radius = 4x10-15 m. Ni atomic number = 28. Ni mass = 9.7x10-26 kg.
 
a) An accelerator accelerates Ni10+ ions through a total potential difference of 6.4 MV. What is the kinetic energy of an ion once it leaves the accelerator?

anonymous · Answer

The Change in kinetic energy is equal to charge times potential difference
$$\Delta KE = e \times V$$

anonymous · Answer

If 10 electrons are removed from Ni it will have 18 electrons. So e = 18 *  1.6 x 10-19 C.