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Mathematics 22 Online
OpenStudy (anonymous):

To prepare for a triathlon, Amanda starts from position A and rides her bike along a straight road for 12 miles to reach position B. At B, she turns left and rides along another straight road for 15 miles to reach position C. At C, she turns left again and rides 20 miles along a straight road to return to A. In ΔABC, what are m∠A, m∠B, and m∠C, respectively?

OpenStudy (anonymous):

|dw:1400439973315:dw|

OpenStudy (anonymous):

@ranga @RosieF @robtobey

OpenStudy (anonymous):

@Johnbc

OpenStudy (anonymous):

Do you know the trigonometric functions for angles and sides of the angles?

OpenStudy (anonymous):

sines and cosines?

OpenStudy (anonymous):

Yup

OpenStudy (anonymous):

Do you know the sides that Sine, Cosine, and tangent relate to?

OpenStudy (anonymous):

not really..

OpenStudy (anonymous):

i know the formulas for sines and cosines

OpenStudy (anonymous):

What are they?

OpenStudy (anonymous):

for sines:\[\frac{ SinA }{ a }=\frac{ SinB }{ b }=\frac{ SinC }{ c }\]

OpenStudy (anonymous):

Cosines:\[a^2=b^2+c^2-2bc*\cos(A)\]

OpenStudy (anonymous):

\[b^2=a^2+c^2-2ac*\cos(B)\]

OpenStudy (anonymous):

\[c^2=a^2+b^2-2ab*\cos(C)\]

OpenStudy (anonymous):

those are the formulas

OpenStudy (anonymous):

Those are definitely the formulas but there are easier forms for angles

OpenStudy (anonymous):

there is?

OpenStudy (anonymous):

|dw:1400442429346:dw|

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

im looking for all 3 angles

OpenStudy (anonymous):

Yup

OpenStudy (anonymous):

And depending on the angle that you want to find first you can use the corresponding formula

OpenStudy (anonymous):

okay so its CAH. Adjacent and Hypotenuse

OpenStudy (ranga):

This is NOT a right triangle. |dw:1400442844816:dw|

OpenStudy (ranga):

Use the Law of Cosines to find angle A. a^2 = b^2 + c^2 - 2bc * cos(A) 15^2 = 20^2 + 12^2 - (2)(20)(12)cos(A). Solve for angle A. Then you can use the Law of Sines to find angle B a / sin(A) = b / sin(B). Then you can find angle C as 180 - angle A - angle B

OpenStudy (anonymous):

im not doing something right, i got 0.84

OpenStudy (ranga):

15^2 = 20^2 + 12^2 - (2)(20)(12)cos(A). 225 = 400 + 144 - 480cos(A) 480cos(A) = 400 + 144 - 225 = 319 cos(A) = 319/480 = 0.6645833 A = arccos(0.664583) = 48.35 degrees.

OpenStudy (anonymous):

okay so m<A= 48.35degress

OpenStudy (ranga):

Find angle B using the Law of Sines.

OpenStudy (anonymous):

94.94 degrees

OpenStudy (ranga):

I have not done the calculation but I will have to assume you did it correctly.

OpenStudy (ranga):

Yes, 94.94 degrees is correct.

OpenStudy (anonymous):

the other angle is 36.71

OpenStudy (ranga):

Yes. Not sure at what decimal place they want you to round off the angles.

OpenStudy (anonymous):

2

OpenStudy (ranga):

okay, then you have the answer.

OpenStudy (anonymous):

okay thank you so much

OpenStudy (ranga):

You are welcome.

OpenStudy (anonymous):

the answer is 48.35°, 94.94°, 36.71°

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