Question

log3 (5) +log3 ( x2+4) =3

Answer 1

\[\log_3 (5) +\log_3 ( x^2+4) =3\]\[\log_3 (5) +\log_3 ( x^2+4) =3 \times \log_33\]\[\log_3 (5) +\log_3 ( x^2+4) =\log_33^3\]\[\log_3 (5) +\log_3 ( x^2+4) =\log_327\]Then apply,\[logA+logB=\log(AB)\]and solve for x

Answer 2

Thank You! But now how do I solve for x?

Answer 3

tell me what do you get after applying
\[\log(a)+\log(b)=\log(a \times b)\]

Answer 4

I dont know what a and b are

Answer 5

in your case, a is 5 and b is x²+4

Answer 6

So then I should get log (5) +log (x²+4) = log (5)(x²+4)

Answer 7

Yes, \[\log_3[~~5(x^2+4)~~~]\]Can you expand the parenthesis inside the log ?

Answer 8

I think you get log3 [5x2 + 20]

Answer 9

yes, correct.

Answer 10

I hate disconnecting !

Answer 11

Made a mistake, sorry. this time it will be correct.

\(\LARGE\color{blue}{ \bf log_3\color{red} { 5x^2+20 } = log_3\color{red} { 27} }\)

Do you see what you can remove/imply ?