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Find all solutions for 2cos^2x+3cosx+1=0
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it's very hard to see ir because of the "Cosx" sign there. Sinve we want to make things more evident and simple to solve we will make a "change of variable". So, let's take a look at the problem: \[2Cos ^{2}x+3Cosx+1=0\] And let's make the change of variable: \[z=Cosx\] And replace it: \[2z ^{2}+3z+1=0\] And now, we formed a quadratic equation wich we can solve with the general formula: \[z=\frac{ -3 \pm \sqrt{3^{2}-4(2)(1)} }{ 2(3) }\] I believe you can go on from here, once you found the values of "z", go to the change of variable and deduce the value of x.
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