Correlations please help
@satellite73
were you able to make the scatter plots?
@jim_thompson5910 I have 2 additional questions on top of this one to do in 40 minutes if you are able to help me please.
Yes.
are you able to use a program/calculator to compute the correlation coefficient?
I used SPSS
ok that works
I've never used it, but I know it's a stats program
Yeah.. but I don't know how to read anything to put it into an answer.. this is what I wrote for that one but I dont know if it's right The correlation coefficient tells a person how close the data is to being linear. The number one tells you that you have a line when you connect all the dots and a 0 would be equally spread out. Correlation coefficients tell you if the data is related as 2 variables increase in certain ways. Never assume causation just because you get high correlation. When they are more linear they have a correlation coefficient closer to one. The correlation coefficient is r^2 which is fairly close to 1. Correlation is how well the data relates, when you increase something by 1, the other variable always increase.
I'm to the point of rushing through it since I have 3 questions to do in 30 minutes now...
yeah you pretty much have the general basics of correlation coefficients if r is near 0, then the data is not really linear (so use another model) if r is near +1, then the data is pretty likely to be linearly correlated with a positive slope if r is near -1, then the data is pretty likely to be linearly correlated with a negative slope of course, correlation does not imply causation
so it sounds like you have it down
Someone else helped me with that one... could you help me with my last 2 questions please
so hopefully I can stop crying and stressing lmao
ok
you'll be fine
Ill post my graph and stuff that I did too
ok go ahead
That's it
so what is the correlation coefficient based on this result SPSS produces?
See that's where I am confused. I'm not sure exactly which number I should be looking at
For some strange reason, they compute the correlation coefficient with a variable and itself (getting a correlation coefficient of 1). I'm not sure why you'd do that since you're always going to get 1 in that case.
The scatter plot shows us we do NOT have a straight line, so the correlation coefficient is clearly not 1.
It turns out that the correlation coefficient is actually 0.14422205 and this is much better since the data is more randomly spread out and not falling near or close to a line
So I look at the GPA one?
and SPSS does produce this result of 0.144 you have to look in the cells which have GPA and hours of study
So I would say my correlation coefficient is 0.144, but how do I explain that?
Well the program produces that value, so you just say that's what SPSS calculated. And it justifies the scatter plot. The dots don't fit near or on a line, so the data is not linear. The r value is closer to 0 than to 1, so the data is not linear
I don't know what the "sig(two tailed)" is referring to, but ignore it
Ok so I would type... My correlation coefficient is 0.144 based on the results of SPSS calculation. It justifies the scatter plot because the points don't fit on or near a line, so the data is not linear. The r value is closer to 0 than to 1, so the data is not linear. Is that right?
yeah, but in your own words that you understand
oK... I have one more thing please
The red is the only answer I think I know
ok one sec
Thank you so much.. I have to leave very soon
sadly I'm not finding much on "predicting the z-score formula", I wonder if they mention that anywhere in your book?
Shoot thank you
yeah I've never heard of it then again, I haven't taken many stats courses (I've yet to dive into multiple regression and such)
I don't know why I'm so confused lol thank you for your help on the others though :)
I might have found something here http://www.learningace.com/doc/7701925/b7621ca500e4a54f7f10a745af4cfa85/chapter-3-correlation-and-prediction but it'll take me a bit of time to read through it
you're welcome
I found that
ok one sec
I looked more and it says Beta is my regression score.
So what we want is \[\Large Z_{y} = \beta*Z_{x}\] but I'm not sure how to find beta
It tells me beta in the first attachmetn
it says the r=.36
are you sure that's beta? it seems too easy
I guess it's the closest thing we have that they give us
I'll attach a couple of steps it says real quick then I have to throw on some make up lol
oh I guess you're right: beta = r
so yeah, it would be \[\Large Z_{y} = 0.36*Z_{x}\]
So how do you think I would do the prediction
in part B, you step 1) calculate Zx, the z-score for similarity for x = 5 step 2) plug Zx into the formula above to find Zy
So do I put 5 in for Zx? so .36*5?
no
x = 5, so the z-score Zx is.. Zx = (x - mu)/SD Zx = (5-3.25)/1.92 Zx = 0.91
Then you plug that into the formula Zy = 0.36*Zx Zy = 0.36*0.91 Zy = 0.3276 Zy = 0.33
So my final answer is the 0.33?
yeah for that part
Sorry I'm getting ready for work at the same time lol
oh wait, you'd then solve for y Zy = (y - M)/SD 0.33 = (y - 6)/2.55 0.33*2.55 = y - 6 0.8415 = y - 6 0.8415+6 = y y = 6.8415 That's the predicted attraction (so around 7)
So to use the formula Zy = beta*Zx, you have to standardize the score first then you unstandardize to get it back to a raw score (the predicted raw score)
So that's for part b? the whole thing you just typed? or just this last one?
they all go together
So all 3 parts? and my final prediction is 7?
hopefully you see how i went from x = 5 to Zx = Zx = 0.91
What about part A?
and how I got Zy = 0.33
part A is just the formula itself
so maybe 2 lines at most
and yeah around 7 I'd say
Ok... so what exactly do I write for part A? sorry I'm rushing you I really appreciate it.
just the formula that you attached, the one with beta then you plug in beta = r = 0.36
Zy = beta*Zx plug in beta = 0.36
So Zy= .36* what?
Zx
for part b, you are plugging in Zx = 0.91 (you have to show how you got Zx = 0.91)
It shows 4 Zx so how do I know which to put?
4Zx? where are you getting 4?
I have no idea lol
it'd be Zy = 0.36*Zx
I'm just replacing beta with 0.36
they just want you to predict Zy based on Zx
you have to compute Zx first though
I don't know how.
I have 4 minutes lol
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