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Mathematics 10 Online
OpenStudy (vshiroky):

Correlations please help

OpenStudy (vshiroky):

OpenStudy (vshiroky):

@satellite73

jimthompson5910 (jim_thompson5910):

were you able to make the scatter plots?

OpenStudy (vshiroky):

@jim_thompson5910 I have 2 additional questions on top of this one to do in 40 minutes if you are able to help me please.

OpenStudy (vshiroky):

Yes.

jimthompson5910 (jim_thompson5910):

are you able to use a program/calculator to compute the correlation coefficient?

OpenStudy (vshiroky):

I used SPSS

jimthompson5910 (jim_thompson5910):

ok that works

jimthompson5910 (jim_thompson5910):

I've never used it, but I know it's a stats program

OpenStudy (vshiroky):

Yeah.. but I don't know how to read anything to put it into an answer.. this is what I wrote for that one but I dont know if it's right The correlation coefficient tells a person how close the data is to being linear. The number one tells you that you have a line when you connect all the dots and a 0 would be equally spread out. Correlation coefficients tell you if the data is related as 2 variables increase in certain ways. Never assume causation just because you get high correlation. When they are more linear they have a correlation coefficient closer to one. The correlation coefficient is r^2 which is fairly close to 1. Correlation is how well the data relates, when you increase something by 1, the other variable always increase.

OpenStudy (vshiroky):

I'm to the point of rushing through it since I have 3 questions to do in 30 minutes now...

jimthompson5910 (jim_thompson5910):

yeah you pretty much have the general basics of correlation coefficients if r is near 0, then the data is not really linear (so use another model) if r is near +1, then the data is pretty likely to be linearly correlated with a positive slope if r is near -1, then the data is pretty likely to be linearly correlated with a negative slope of course, correlation does not imply causation

jimthompson5910 (jim_thompson5910):

so it sounds like you have it down

OpenStudy (vshiroky):

Someone else helped me with that one... could you help me with my last 2 questions please

OpenStudy (vshiroky):

so hopefully I can stop crying and stressing lmao

jimthompson5910 (jim_thompson5910):

ok

jimthompson5910 (jim_thompson5910):

you'll be fine

OpenStudy (vshiroky):

OpenStudy (vshiroky):

Ill post my graph and stuff that I did too

jimthompson5910 (jim_thompson5910):

ok go ahead

OpenStudy (vshiroky):

OpenStudy (vshiroky):

That's it

jimthompson5910 (jim_thompson5910):

so what is the correlation coefficient based on this result SPSS produces?

OpenStudy (vshiroky):

See that's where I am confused. I'm not sure exactly which number I should be looking at

jimthompson5910 (jim_thompson5910):

For some strange reason, they compute the correlation coefficient with a variable and itself (getting a correlation coefficient of 1). I'm not sure why you'd do that since you're always going to get 1 in that case.

jimthompson5910 (jim_thompson5910):

The scatter plot shows us we do NOT have a straight line, so the correlation coefficient is clearly not 1.

jimthompson5910 (jim_thompson5910):

It turns out that the correlation coefficient is actually 0.14422205 and this is much better since the data is more randomly spread out and not falling near or close to a line

OpenStudy (vshiroky):

So I look at the GPA one?

jimthompson5910 (jim_thompson5910):

and SPSS does produce this result of 0.144 you have to look in the cells which have GPA and hours of study

OpenStudy (vshiroky):

So I would say my correlation coefficient is 0.144, but how do I explain that?

jimthompson5910 (jim_thompson5910):

jimthompson5910 (jim_thompson5910):

Well the program produces that value, so you just say that's what SPSS calculated. And it justifies the scatter plot. The dots don't fit near or on a line, so the data is not linear. The r value is closer to 0 than to 1, so the data is not linear

jimthompson5910 (jim_thompson5910):

I don't know what the "sig(two tailed)" is referring to, but ignore it

OpenStudy (vshiroky):

Ok so I would type... My correlation coefficient is 0.144 based on the results of SPSS calculation. It justifies the scatter plot because the points don't fit on or near a line, so the data is not linear. The r value is closer to 0 than to 1, so the data is not linear. Is that right?

jimthompson5910 (jim_thompson5910):

yeah, but in your own words that you understand

OpenStudy (vshiroky):

oK... I have one more thing please

OpenStudy (vshiroky):

The red is the only answer I think I know

jimthompson5910 (jim_thompson5910):

ok one sec

OpenStudy (vshiroky):

Thank you so much.. I have to leave very soon

jimthompson5910 (jim_thompson5910):

sadly I'm not finding much on "predicting the z-score formula", I wonder if they mention that anywhere in your book?

OpenStudy (vshiroky):

Shoot thank you

jimthompson5910 (jim_thompson5910):

yeah I've never heard of it then again, I haven't taken many stats courses (I've yet to dive into multiple regression and such)

OpenStudy (vshiroky):

I don't know why I'm so confused lol thank you for your help on the others though :)

jimthompson5910 (jim_thompson5910):

I might have found something here http://www.learningace.com/doc/7701925/b7621ca500e4a54f7f10a745af4cfa85/chapter-3-correlation-and-prediction but it'll take me a bit of time to read through it

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (vshiroky):

OpenStudy (vshiroky):

I found that

jimthompson5910 (jim_thompson5910):

ok one sec

OpenStudy (vshiroky):

I looked more and it says Beta is my regression score.

jimthompson5910 (jim_thompson5910):

So what we want is \[\Large Z_{y} = \beta*Z_{x}\] but I'm not sure how to find beta

OpenStudy (vshiroky):

It tells me beta in the first attachmetn

OpenStudy (vshiroky):

it says the r=.36

jimthompson5910 (jim_thompson5910):

are you sure that's beta? it seems too easy

jimthompson5910 (jim_thompson5910):

I guess it's the closest thing we have that they give us

OpenStudy (vshiroky):

I'll attach a couple of steps it says real quick then I have to throw on some make up lol

OpenStudy (vshiroky):

OpenStudy (vshiroky):

jimthompson5910 (jim_thompson5910):

oh I guess you're right: beta = r

jimthompson5910 (jim_thompson5910):

so yeah, it would be \[\Large Z_{y} = 0.36*Z_{x}\]

OpenStudy (vshiroky):

So how do you think I would do the prediction

jimthompson5910 (jim_thompson5910):

in part B, you step 1) calculate Zx, the z-score for similarity for x = 5 step 2) plug Zx into the formula above to find Zy

OpenStudy (vshiroky):

So do I put 5 in for Zx? so .36*5?

jimthompson5910 (jim_thompson5910):

no

jimthompson5910 (jim_thompson5910):

x = 5, so the z-score Zx is.. Zx = (x - mu)/SD Zx = (5-3.25)/1.92 Zx = 0.91

jimthompson5910 (jim_thompson5910):

Then you plug that into the formula Zy = 0.36*Zx Zy = 0.36*0.91 Zy = 0.3276 Zy = 0.33

OpenStudy (vshiroky):

So my final answer is the 0.33?

jimthompson5910 (jim_thompson5910):

yeah for that part

OpenStudy (vshiroky):

Sorry I'm getting ready for work at the same time lol

jimthompson5910 (jim_thompson5910):

oh wait, you'd then solve for y Zy = (y - M)/SD 0.33 = (y - 6)/2.55 0.33*2.55 = y - 6 0.8415 = y - 6 0.8415+6 = y y = 6.8415 That's the predicted attraction (so around 7)

jimthompson5910 (jim_thompson5910):

So to use the formula Zy = beta*Zx, you have to standardize the score first then you unstandardize to get it back to a raw score (the predicted raw score)

OpenStudy (vshiroky):

So that's for part b? the whole thing you just typed? or just this last one?

jimthompson5910 (jim_thompson5910):

they all go together

OpenStudy (vshiroky):

So all 3 parts? and my final prediction is 7?

jimthompson5910 (jim_thompson5910):

hopefully you see how i went from x = 5 to Zx = Zx = 0.91

OpenStudy (vshiroky):

What about part A?

jimthompson5910 (jim_thompson5910):

and how I got Zy = 0.33

jimthompson5910 (jim_thompson5910):

part A is just the formula itself

jimthompson5910 (jim_thompson5910):

so maybe 2 lines at most

jimthompson5910 (jim_thompson5910):

and yeah around 7 I'd say

OpenStudy (vshiroky):

Ok... so what exactly do I write for part A? sorry I'm rushing you I really appreciate it.

jimthompson5910 (jim_thompson5910):

just the formula that you attached, the one with beta then you plug in beta = r = 0.36

jimthompson5910 (jim_thompson5910):

Zy = beta*Zx plug in beta = 0.36

OpenStudy (vshiroky):

So Zy= .36* what?

jimthompson5910 (jim_thompson5910):

Zx

jimthompson5910 (jim_thompson5910):

for part b, you are plugging in Zx = 0.91 (you have to show how you got Zx = 0.91)

OpenStudy (vshiroky):

It shows 4 Zx so how do I know which to put?

jimthompson5910 (jim_thompson5910):

4Zx? where are you getting 4?

OpenStudy (vshiroky):

I have no idea lol

jimthompson5910 (jim_thompson5910):

it'd be Zy = 0.36*Zx

jimthompson5910 (jim_thompson5910):

I'm just replacing beta with 0.36

jimthompson5910 (jim_thompson5910):

they just want you to predict Zy based on Zx

jimthompson5910 (jim_thompson5910):

you have to compute Zx first though

OpenStudy (vshiroky):

I don't know how.

OpenStudy (vshiroky):

I have 4 minutes lol

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