Question

can someone please help me with factoring! MEDAL AWARDED

22x^2+50x+12

Answer 1

How would we begin o factor this out?

Answer 2

using the x-box method i believe

Answer 3

\[22x^2+50x+12\]

Answer 4

it's 6*44

Answer 5

2(11x+3)(x+2)

Answer 6

6+44=50, and 6*44=264

Answer 7

There is not 264 in your original un-factored polynomial

Answer 8

\[\large 2(11x^2+25x+6)\]

First step, factor out 2.

Now find factors of 11 x 6 whose sum is 25.

Factoring the quadratic

\[\large 11x^2+25x+6 ~ => ~ 11x^2+22x+3x+6 \]

Because the product of 11 and 6 is 66. The factors of 66 which sum to 25 are 3 and 22. So ,

\[\large 11x^2+22x+3x+6 ~ => ~ 2(11x+3)+x(11x+3)\]

Factor out the common terms now

\[\large 2(11x+3)(x+2)\]

Answer 9

how would to factor the 2(11x+3)(x+2)?

Answer 10

You don't that's the final answer.

Answer 11

It can not be "factored", the factoring shows the polynomial function of higher degrees to lower as you may notice there is no longer an x^2

Answer 12

but don't you need to find the roots? the x values setting 2(11x+3)(x+2)=0?

Answer 13

Is it asking you to find the roots?

Answer 14

yes

Answer 15

Alright so basically you just solve for x then, 11x+3 = 0, and x+2 = 0, doing that you get x = -2, and x = -3/11 :)!

Answer 16

:) thanks so much!

Answer 17

Np ^.^